CTR K
Structural Steel Sections

Section library, properties & EN 1993-1-1 combined stress check

200 × 100 mm · A 28.50 cm² · I_y 1940 cm⁴ ·22.4 kg/m

European sections to EN 1993-1-1. For AISC W and S properties see the Reference Library — an American shape is designed to AISC 360 with an ASTM grade, not to Eurocode.

Steel grade

f_y = 355 MPa · ε = 0.8136 · Class 1

= L
M_Ed90.00 kN·m
V_Ed60.00 kN
N_Ed0.00 kN
GOVERNING UTILISATIONi
FAIL
6.669η
LTB controls · SF 0.15 · IPE 200 · S355 · Class 1 · limit η ≤ 1.0
CROSS-SECTION — EN 1993-1-1 §5.5 CLASSIFICATION
IPE · ε=0.814
b 100.0mmh 200.0mmtf 8.5mmtw 5.6mmSECTION CLASSIFICATIONε = √(235/fy) = √(235/355) = 0.814flange c/tf = 4.14 9ε = 7.32c = b/2 − tw/2 − r = 35.2mmweb c/tw = 28.4 72ε = 58.6c = h − 2tf − 2r = 159.0mmsection (hatched)flange outstand cweb clear depth ccentroidal axes
Iy — 2nd momenti
1940cm⁴
major axis
Wy,el — section modulusi
194.0cm³
elastic
Bending η₁ = M/M_Rdi
1.147η
90.0 / 78.5 kN·m
Governing safety factor — LTBi
0.15nS
check exceeded
FAIL — LTB governs at η = 6.669 (limit 1.0)
IPE 200 · S355 · L=6.00 m · Section Class 1 · load on the top flange

European Steel Sections Calculator — Section Properties, Unity Checks & LTB (EN 1993-1-1)

Governing standard: EN 1993-1-1· EN 1993-1-1:2005 (Eurocode 3, Part 1-1) · §5.5 / Table 5.2 section classification · §6.2 cross-section resistance · §6.2.8 shear-moment interaction · §6.3.2.2 lateral-torsional buckling (general case, curve b) · §6.2.9 M-N interaction

Page last updated

How EN 1993-1-1 works — the method explained

The MechanixCalc steel sections calculator provides tabulated section properties and full cross-section resistance checks to EN 1993-1-1 (Eurocode 3, Part 1-1). Select any section from a built-in library of 174 European profiles — IPE, HEA and HEB to EN 10365, and RHS, SHS and CHS to EN 10219 / EN 10210 — define the steel grade (S235 to S460), enter the span and loads, and the tool instantly returns the bending, shear and axial unity checks, the lateral-torsional buckling (LTB) reduction factor and buckling moment resistance, the M-N interaction check, and the deflection under both the distributed and the point load for the actual support condition, checked against an L/300 serviceability target.

It is designed for structural and civil engineers who need to select and verify steel members quickly to the Eurocode — checking a floor beam, crane girder, column, hollow section strut or any structural frame member — and who need to hand a reviewer a complete, standards-cited calculation rather than a back-of-envelope lookup. Everything sits on one page: pick the profile and grade in the input panel, read the governing utilisation at the top, and open the sections below for the full property sheet, the unity checks, the moment and shear diagrams, a side-by-side comparison of up to three profiles, plastic-hinge analysis, a bolted-connection check and the searchable library of all 174 profiles.

What this calculator does

  • EN 1993-1-1 section classification (Class 1–4) using the right Table 5.2 sheet per element — outstand limits for I/H flanges, internal-part limits for webs and hollow walls (with the web classified for the axial compression it carries), and d/t for circular hollow sections
  • Bending, shear and axial unity checks per Eurocode 3 §6.2 (elastic and plastic resistances with γ_M0 = 1.0)
  • Lateral-torsional buckling (LTB) check with χ_LT reduction factor and design buckling moment resistance M_b,Rd (EN 1993-1-1 §6.3.2.2 general case, curve b), or a fully-restrained compression flange declared explicitly
  • M-N interaction diagram for combined bending and axial load per EN 1993-1-1 §6.2.9 (Class 1/2 linear boundary)
  • Compression with bending checked against a conservative Method 2 bound of EN 1993-1-1 §6.3.3 Eq. 6.61 / 6.62 (Annex B with C_m = 1 and buckling curve c, rolled sections): at or below 1 it passes, above 1 the tool returns NO RESULT rather than a verdict it cannot support
  • Deflection under UDL AND point load, using the formula for the actual support condition (simply supported, cantilever, fixed-fixed or propped), checked against an L/300 target
  • Side-by-side section comparison with radar chart (Iy, Iz, Wy,el, mass, height) and material-efficiency index (Wy,el / mass)
  • One governing utilisation across every check — bending, shear, axial, combined, deflection, LTB and the §6.3.3 Method 2 compression-with-bending bound — read identically by the on-screen verdict, the PDF report and the AI assistant
  • Branded PDF engineering report with the full Eurocode method, section sketch and all intermediate results shown

Method & formulas

Section classification (EN 1993-1-1 §5.5)

Eurocode 3 classifies each element of the cross-section (flange outstand and web) based on the ratio of the element's compression width c to its thickness t. The slenderness limits are scaled by the factor ε = √(235 / fy), which corrects for steel grade — higher-strength steels have a lower ε and therefore stricter limits. A Class 1 section can form a full plastic hinge; Class 2 can reach plastic moment but cannot sustain it for moment redistribution; Class 3 can reach the elastic moment in extreme fibre; and a Class 4 section undergoes local buckling before any yield, requiring effective-section reduction.

The calculator evaluates both the flange outstand (c/t_f) and the web (c/t_w) and reports the governing class, which determines whether the elastic modulus W_el or plastic modulus W_pl is used in the resistance formulas.

Slenderness correction factor
ε = √(235 / fy)

where ε = Eurocode 3 slenderness factor (dimensionless); fy = yield strength of the steel grade (MPa). ε = 1.0 for S235, ≈ 0.924 for S275, ≈ 0.814 for S355.

Flange outstand class limits (rolled I-section)
c / tf ≤ 9ε → Class 1; ≤ 10ε → Class 2; ≤ 14ε → Class 3

where c = flange outstand = (b/2 − tw/2 − r) (mm); tf = flange thickness (mm); tw = web thickness (mm); r = root fillet radius (mm); b = total flange width (mm).

Cross-section resistance checks (EN 1993-1-1 §6.2)

For Class 1 and 2 sections the plastic modulus W_pl is used for the bending resistance; for Class 3 the elastic modulus W_el governs. The shear resistance uses the shear area A_v (the load-carrying web area) derived per §6.2.6 depending on section type. The axial plastic resistance is N_pl,Rd = A · fy / γ_M0. Unity checks (η = action / resistance) are computed for bending, shear and axial force individually, and the combined M-N interaction is checked graphically against the §6.2.9 simplified boundary.

Bending resistance (Class 1/2, plastic; γ_M0 = 1.0)
M_c,Rd = W_pl · fy / γ_M0

where M_c,Rd = design moment resistance (kN·m); W_pl = plastic section modulus about strong axis (mm³); fy = yield strength (MPa); γ_M0 = 1.0 (partial factor for cross-section resistance, EN 1993-1-1 §6.1).

Shear resistance
V_pl,Rd = Av · fy / (√3 · γ_M0)

where V_pl,Rd = design plastic shear resistance (kN); Av = shear area (mm²) per §6.2.6; fy = yield strength (MPa); √3 appears from the von Mises yield criterion.

Lateral-torsional buckling (EN 1993-1-1 §6.3.2.2)

When an unrestrained I-section beam is loaded in bending it can buckle laterally before reaching the cross-section moment resistance. Eurocode 3 §6.3.2.2 — the general case — quantifies this via the non-dimensional LTB slenderness λ̄_LT = √(W_y · fy / M_cr), where M_cr is the elastic critical moment and W_y is W_pl,y for a Class 1 or 2 section and W_el,y for Class 3 (§6.3.2.1(3)). The χ_LT reduction factor (buckling curve b, imperfection factor α_LT = 0.34) then scales the cross-section resistance to give the design buckling moment resistance M_b,Rd. The LTB check is expressed as a unity ratio η_LTB = M_Ed / M_b,Rd ≤ 1. The calculator uses §6.3.2.2 rather than the §6.3.2.3 rolled-section method, which makes it the more conservative of the two by roughly 8 to 20 % on χ_LT; if the compression flange is continuously restrained you can declare that instead, and the check is then not applied.

The elastic critical moment M_cr is calculated from the Saint-Venant torsional stiffness (GI_t), the warping stiffness (EI_w) and the weak-axis flexural stiffness (EI_z) of the section, over the laterally unrestrained length L_cr. Where the load acts matters: a load bearing on the top flange twists the section further as it buckles and lowers M_cr, so the calculator asks for the load position and takes the top flange by default.

A cantilever has a fixed base and a free tip, and whether the base prevents warping depends on a detail the calculator does not model, so it reads lateral-torsional buckling both ways. With the base preventing warping, a tip load or UDL uses the form above over L_cr (C1 = 1 stays at or below the value for a base that prevents warping), while a moment typed in by hand, whose distribution is unknown, is taken as uniform over 2·L_cr. With the base free to warp, M_cr = γ·√(E·Iz·G·It)/L_cr with I_w ignored. The larger utilisation is stated, and when only the free-warping one exceeds 1 the result is NO RESULT.

Elastic critical moment (uniform moment, C1 = 1)
M_cr = C1 · (π²·E·Iz / L_cr²) · √(Iw/Iz + L_cr²·G·It / (π²·E·Iz))

where M_cr = elastic critical moment (kN·m); E = 210 000 MPa (Young's modulus); G = 80 770 MPa = E/2(1+0.3) — EN 1993-1-1 §3.2.6 quotes G of about 81 000 MPa, a 0.3 % difference; Iz = second moment of area about weak axis (mm⁴); It = Saint-Venant torsion constant (mm⁴); Iw = warping constant = Iz·(h−tf)²/4 (mm⁶); L_cr = laterally unrestrained length (mm); C1 = 1.0 for uniform moment (conservative). NOTE: EN 1993-1-1:2005 publishes no expression for M_cr — this is the standard doubly-symmetric form for a load through the shear centre; a load on the top flange is taken by the reduction below.

Load applied on the top flange
1 / M_cr = 1 / M_cr,sc + z_g / (k · GJ_eff); GJ_eff = G·It + π²·E·Iw / L_t²

where M_cr,sc = the critical moment with the load at the shear centre; z_g = h/2, the height of the load above the shear centre; k = 0.5 for a fixed-fixed span (its design moment is PL/8 or wL²/12, so there is twice the load per unit moment) and for a moment entered by hand (end moments can halve it), 1 otherwise; L_t = L_cr for a span, 2·L_cr for a cantilever whose base prevents warping, and GJ_eff = G·It alone when the base is free to warp. As z_g → 0 it returns M_cr,sc; for a short, deep member it tends to k·GJ_eff/z_g. A conservative closed form checked against a finite-element solution with the load-height term, for loads bearing on the flange; a downward load hung from the bottom flange is taken at the shear centre, an upward one as destabilising. It covers loads acting the same way within one unrestrained length no longer than the span.

Cantilever with the base free to warp
M_cr = γ · √(E·Iz·G·It) / L_cr; γ = π/2 (uniform moment), 4.01 + 2.41·(1 − β)² otherwise

where γ = moment-shape factor on the base moment, with the warping stiffness E·I_w ignored (it can only raise M_cr); β = F·L / (F·L + w·L²/2), the share of the base moment from the tip load F, so γ = 4.01 for a tip load and 6.42 for a UDL; a moment entered by hand is taken as uniform (γ = π/2). This is the shear-centre value; a top-flange load reduces it by the formula above with GJ_eff = G·It.

LTB reduction factor (buckling curve b, α_LT = 0.34)
χ_LT = 1 / (Φ_LT + √(Φ_LT² − λ̄_LT²)) ≤ 1; Φ_LT = 0.5·[1 + α_LT·(λ̄_LT − 0.2) + λ̄_LT²]

where χ_LT = LTB reduction factor (≤ 1); λ̄_LT = √(Wy·fy / M_cr) = non-dimensional LTB slenderness; α_LT = 0.34, the Table 6.3 imperfection factor for buckling curve b; Φ_LT = intermediate factor. Curve b is applied to every rolled section — Table 6.4 would permit curve a at h/b ≤ 2, which 57 of the 78 open library rows satisfy, so this is deliberately conservative.

Worked example

Check an IPE 300 beam in S355 steel, simply supported over a span of 5 m, carrying a uniformly distributed load of 10 kN/m. Determine the section class, the plastic bending unity check, the shear unity check, the mid-span deflection against an L/300 target, and the lateral-torsional buckling check over the full 5 m unrestrained span.

Given

  • SectionIPE 300 (Wy,el = 557 cm³, Wy,pl = 628 cm³, Iy = 8 360 cm⁴, A = 53.8 cm²)
  • Steel gradeS355 (fy = 355 MPa)
  • Span L5 m (simply supported)
  • UDL w10 kN/m (applied load)
  • Lateral restraintNone over the 5 m span (full restraint shown at the end)
  • Load applied atTop flange (the calculator's default)

Result

  • Section classClass 1 (fully plastic, both flange and web)
  • Plastic moment resistance M_c,Rd222.94 kN·m
  • Design moment M_Ed31.25 kN·m
  • Bending unity check η_M0.140 (PASS)
  • Shear resistance V_pl,Rd526.1 kN (A_v = 25.67 cm²)
  • Shear unity check η_V0.048 (PASS)
  • Mid-span deflection δ4.64 mm — η_δ = 0.278 against an L/300 target of 16.67 mm (PASS)
  • Elastic critical moment M_cr68.02 kN·m on the top flange (113.16 kN·m at the shear centre)
  • LTB resistance M_b,Rd55.63 kN·m (λ̄_LT = 1.8105, χ_LT = 0.2495)
  • LTB unity check η_LT0.562 (PASS)
  • Governing utilisation0.562 — LTB governs; safety factor 1.78
  1. Section classification: ε = √(235 / 355) = √0.662 = 0.814. For IPE 300: c/tf = (150/2 − 7.1/2 − 15) / 10.7 = (75 − 3.55 − 15) / 10.7 = 56.45 / 10.7 = 5.28. Limit for Class 1 flange: 9ε = 9 × 0.814 = 7.32 > 5.28 → Class 1 flange.
  2. Web: c/tw = (300 − 2 × 10.7 − 2 × 15) / 7.1 = (300 − 21.4 − 30) / 7.1 = 248.6 / 7.1 = 35.0. Limit for Class 1 web: 72ε = 72 × 0.814 = 58.6 > 35.0 → Class 1 web. Overall section: Class 1.
  3. Bending resistance (plastic, Class 1): M_c,Rd = W_pl · fy / γ_M0 = 628 cm³ × 355 MPa / 1.0 = 628 × 10³ mm³ × 355 N/mm² / 10⁶ = 222.9 kN·m.
  4. Design bending moment: M_Ed = w · L² / 8 = 10 × 5² / 8 = 31.25 kN·m. Bending unity check: η_M = M_Ed / M_c,Rd = 31.25 / 222.9 = 0.140 ≤ 1.0 → PASS.
  5. Shear area (rolled I-section, EN 1993-1-1 §6.2.6(3)): A_v = A − 2·b·tf + (tw + 2r)·tf, working in mm² and converting once. 2·b·tf = 2 × 150 × 10.7 = 3 210 mm²; (tw + 2r)·tf = (7.1 + 30) × 10.7 = 396.97 mm². A_v = 5 380 − 3 210 + 396.97 = 2 566.97 mm² = 25.67 cm². This must not fall below η·h_w·t_w = (300 − 21.4) × 7.1 = 1 977.8 mm² = 19.78 cm², and it does not.
  6. Shear resistance: V_pl,Rd = A_v · fy / (√3 · γ_M0) = 2 566.97 × 355 / (1.732 × 1.0) = 526 100 N = 526.1 kN. Design shear: V_Ed = w · L / 2 = 10 × 5 / 2 = 25 kN. Unity check: η_V = 25 / 526.1 = 0.048 ≤ 1.0 → PASS. Since V_Ed is well below 0.5·V_pl,Rd, the §6.2.8 shear-moment interaction does not apply.
  7. Deflection — simply supported, UDL only (F = 0), so δ = 5·w·L⁴ / (384·E·Iy). With w = 10 kN/m ≡ 10 N/mm, L = 5 000 mm and Iy = 8 360 cm⁴ = 8.36×10⁷ mm⁴: δ = 5 × 10 × 6.25×10¹⁴ / (384 × 210 000 × 8.36×10⁷) = 3.125×10¹⁶ / 6.742×10¹⁵ = 4.64 mm. Target: L/300 = 5 000 / 300 = 16.67 mm → η_δ = 0.278, PASS. Had the same load arrived as a mid-span point load, the FL³/48EI term would have applied instead; had the member been a cantilever, δ = wL⁴/8EI — 9.6× the simply-supported value.
  8. Lateral-torsional buckling over the full 5 m unrestrained span (EN 1993-1-1 §6.3.2.2): with Iz = 604 cm⁴, I_t = 18.69 cm⁴ (computed from the nominal dimensions) and I_w = Iz·(h − tf)²/4 = 1.264×10¹¹ mm⁶, the elastic critical moment with the load at the shear centre is M_cr,sc = 113.16 kN·m. The load bears on the top flange, z_g = h/2 = 150 mm above the shear centre: GJ_eff = G·I_t + π²·E·I_w/L² = 1.5096×10¹⁰ + 1.0477×10¹⁰ = 2.5573×10¹⁰ N·mm² (k = 1 on a simply supported span), and 1/M_cr = 1/113.16×10⁶ + 150/2.5573×10¹⁰, so M_cr = 68.02 kN·m.
  9. Class 1, so W_y = W_pl,y = 628 cm³: λ̄_LT = √(628×10³ × 355 / 68.016×10⁶) = 1.8105. Φ_LT = 0.5[1 + 0.34(1.8105 − 0.2) + 1.8105²] = 2.4127, χ_LT = 0.24954, M_b,Rd = 0.24954 × 628×10³ × 355 / 10⁶ = 55.63 kN·m. η_LT = 31.25 / 55.63 = 0.562. (With the load through the shear centre: λ̄_LT 1.404, χ_LT 0.380, M_b,Rd 84.76 kN·m, η_LT 0.369.)
  10. Governing check: the maximum of η_M 0.140, η_V 0.048, η_δ 0.278 and η_LT 0.562 — LTB governs at η = 0.562, so the beam passes with a governing safety factor of 1.78. Ticking "compression flange fully restrained" removes the LTB check, after which deflection governs at η = 0.278.

Illustrative example — recompute against your own geometry, loading and load combinations, and note that the loads here are used exactly as entered rather than factored by the tool. Every figure above is reproduced by the shipped engine and pinned by a golden test; L/300 is a common serviceability target, not a code requirement.

Frequently asked questions

Which standard does the steel sections calculator use?

Cross-section resistance checks (bending, shear, axial, shear-moment interaction and M-N interaction) follow EN 1993-1-1:2005 (Eurocode 3, Part 1-1), §6.2. Section classification uses §5.5 and Table 5.2 — sheet 2 outstand limits for I/H flanges, sheet 1 internal-part limits for the webs and for both walls of a rectangular or square hollow section (a web in bending uses 72ε / 83ε / 124ε; under axial compression its limits come from the plastic compression-zone ratio α and the elastic stress ratio ψ, falling towards 33ε / 38ε / 42ε, so a slender web such as IPE 600 in S460 becomes Class 3 or Class 4 as N_Ed rises; a Class 4 section returns NO RESULT unless a check on the gross section already fails, which the effective section could not improve), and sheet 3 (d/t against 50ε² / 70ε² / 90ε²) for circular hollow sections. Lateral-torsional buckling is evaluated to §6.3.2.2, the general case (buckling curve b, α_LT = 0.34). With axial compression and bending together, §6.3.3 is checked as a conservative upper bound of Eq. 6.61 / 6.62 by Method 2 (Annex B with C_my = C_mLT = 1, buckling curve c on both axes); member buckling on its own (§6.3.1) is indicative only — flexural about the smaller radius of gyration and, for I-sections, torsional (§6.3.1.4), whichever reduces more; a cantilever I-section whose torsional or lateral-torsional buckling check passes only with a base that prevents warping reads NO RESULT. The deflection check uses standard elastic beam theory for the chosen support condition and is compared to an L/300 target — note that EN 1993-1-1 §7.2 and EN 1990 A1.4 leave deflection limits to the National Annex and to project agreement, so L/300 is a common default rather than a code requirement. γ_M0 = γ_M1 = 1.0 and γ_M2 = 1.25 are recommended values and are Nationally Determined Parameters. The governing standard and clause references are shown in the generated PDF report.

Which section profiles are in the library?

174 European profiles: hot-rolled I-profiles (IPE, HEA, HEB) plus rectangular, square and circular hollow sections (RHS, SHS, CHS). The I/H profile properties are the EN 10365 tabulated values, except the torsion constant I_t, which is computed from the nominal dimensions. The hollow sections are computed from their EN 10210-2 / EN 10219-2 designation — h × b × t, depth first — including the EN 10219-2 cold-formed corner radii, which brings their areas and masses to within 0.1 % of catalogue (SHS 200×8 gives 59.24 cm² and 46.5 kg/m). American AISC W and S shapes are deliberately NOT in this tool: a W-shape is designed to AISC 360 with an ASTM grade such as A992 (Fy = 50 ksi), not to EN 1993-1-1 with S235, so checking one here would mix two codes. AISC section properties are available in the Reference Library, which is a lookup and applies no design code. Every computed row is labelled as such in the tool; check against the producer catalogue before final design. The full library is searchable and filterable by profile type in the "Section library" section at the foot of the page.

Does the calculator check lateral-torsional buckling?

Yes — for open I/H-sections (IPE, HEA and HEB) the LTB check is performed per EN 1993-1-1 §6.3.2.2. Enter the laterally unrestrained length L_cr, or tick the fully-restrained option if decking, a slab or bracing restrains the compression flange continuously, in which case §6.3.2 is not applied. The tool computes the elastic critical moment M_cr from the section torsional and warping properties (for a cantilever whose base is free to warp, from the torsional and weak-axis stiffness alone) and the load position — top flange by default, which lowers M_cr; shear centre; or hung from the bottom flange, taken at the shear centre — the non-dimensional slenderness λ̄_LT, the χ_LT reduction factor (curve b) and the design buckling moment resistance M_b,Rd. A cantilever is read with its base both preventing and free to warp, and a moment typed in by hand on a cantilever is taken as uniform (the most onerous case). For closed hollow sections (RHS, SHS, CHS) the torsional stiffness makes lateral-torsional buckling non-critical in normal building cases, so the cross-section resistance governs directly and no LTB check is reported.

Does the calculator check web shear buckling?

No — it detects when the check is required and then withholds the verdict. EN 1993-1-1 §6.2.6(6) sends a web to the EN 1993-1-5 §5 shear-buckling check when h_w/t_w > 72ε/η; the tool takes η = 1.2, the EN 1993-1-5 recommended value up to S460, which puts the limit at 60ε (the conservative reading for this limit). In the library that applies to IPE 400 and IPE 450 in S460 and to IPE 500, 550 and 600 in S420 and S460. While such a web carries shear the tool returns NO RESULT instead of a verdict based on the plastic shear resistance V_pl,Rd, which the web may not reach — unless a check already fails, in which case the FAIL stands. Verify those webs to EN 1993-1-5 §5 separately.

Can I compare multiple sections?

Yes — open the "Compare sections" section and select up to three profiles. It shows a radar chart normalised to the maximum in each property (Iy, Iz, Wy,el, height, mass), a side-by-side property table, an efficiency index (Wy,el / mass) to identify the most material-efficient profile for your load case, and the M-N interaction diagram for the currently selected section. A separate "Shape efficiency at equal area" section ranks the generic forms — solid square and round, square and round hollow, I-section and channel — at one cross-sectional area, using the second moment of area for bending, the radius of gyration for axial load and the St-Venant torsion constant for torsion.

Is the steel sections calculator free?

Yes — the Steel Sections tool is fully free with no login required. You can access section properties and all EN 1993-1-1 checks immediately. A free 30-minute preview of the wider MechanixCalc suite is available with no sign-up, and a free 14-day account trial (no credit card required) unlocks every paid calculator. The branded PDF engineering report and saved calculations are included in the free 14-day trial and in every paid plan.

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